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Topic: Investigations
Subject: Calculation Q and F
 
Author: MUNIF CELEBI 2005-12-17  
     
  Dear all,
After calculation of Q (Normalized Cone Resistance) and F( Normalized Friction Ratio) if our results grater than 1000 for Q and grater than 10 for F, What does it mean.

MUNIF
 
   

 

Follow-up:
  Author: T. Stevens, UniSoft Ltd. 2006-06-01  
     
  June 1, 2006

Dear Mr. Celeby,

Thanks for sending me the CPTU soundings. I found the profile to consist of a one metre surficial sand layer on a 32 m thick layer of soft clay deposited directly on a sand layer at the end of the sounding. Because the cone stress is small, the friction ratio gets to exceed 10 % for some data points. The 10 % is the upper boundary for the Robertson classification chart. Presumably, Robertson did not have CPTU data with a friction ratio larger than 10 %. If the data are plotted in a Robertson chart with the friction ratio axis extended beyond 10 %, it looks logical to simply extrapolate Robertson's boundary lines for the different classification areas.

However, you can avoid the quandary by using the Eslami-Fellenius classification approach. The E-F classification is essentially the same as in the Robertson 1990 method, which supports the mentioned “logical” extrapolation of the boundaries.

Best regards,

Ted Stevens
 
     
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Follow-ups:

» T. Stevens, 2006-01-08
» Paul W. Mayne, 2006-01-19
» Bengt H. Fellenius, 2006-01-20
» Maxim, 2006-05-29
» T. Stevens, 2006-06-01
» T. Stevens, UniSoft Ltd., 2006-06-01

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